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If $a, b, c, \neq 0$ and belong to the set to $\{0,1,2$, $3 \ldots \ldots, 9\}$, then
$\log _{10}\left(\frac{a+10 b+10^2 c}{10^{-4} a+10^{-3} b+10^{-2} c}\right)$ is equal to
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$\log _{10}\left(\frac{a+10 b+10^2 c}{10^{-4} a+10^{-3} b+10^{-2} c}\right)$ is equal to
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Verified Answer
The correct answer is:
4
$\begin{aligned} & \log _{10}\left(\frac{a+10 b+10^2 c}{10^{-4} a+10^{-3} b+10^{-2} c}\right) \\ & =\log _{10}\left(\frac{a+10 b+10^2 c}{\frac{1}{10^4}\left(a+10 b+10^2 c\right)}\right)=\log _{10} 10^4=4\end{aligned}$
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