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If $A, B, C$ are any three arbitrary events, then which one of the following expressions shows that both $A$ and $B$ occur but not $C$ ?
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The correct answer is:
$A \cap B \cap \bar{C}$
If $\mathrm{A}, \mathrm{B}, \mathrm{C}$ are any three arbitary events then only expression $A \cap B \cap \bar{C}$ will show that both $A$ and $B$ occur but not $\mathrm{C}$.
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