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If $a, b, c$ are in A.P., then $\frac{a}{b c}, \frac{1}{c}, \frac{2}{b}$ are in
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None of these
$a, b, c$ be in A.P. then divide each term by $b c$, we get $\frac{a}{b c}, \frac{1}{c}, \frac{1}{b}$ be in A.P. But it is $\frac{2}{b}$ in place of $\frac{1}{b}$, so answer is (4)
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