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If $\mathbf{A}=\mathbf{B}+\mathbf{C}$ have scalar magnitudes of 5,4,3 units respectively, then the angle between $A$ and $\mathbf{C}$ is
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1915 Upvotes
Verified Answer
The correct answer is:
$\cos ^{-1}(3 / 5)$
Here, triangle is
$\theta=\cos ^{-1}\left(\frac{|\mathbf{C}|}{|\mathbf{A}|}\right)$
$\theta=\cos ^{-1}\left(\frac{3}{5}\right)$
$\theta=\cos ^{-1}\left(\frac{|\mathbf{C}|}{|\mathbf{A}|}\right)$
$\theta=\cos ^{-1}\left(\frac{3}{5}\right)$
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