If A ⊆ B , then which one of the following is not correct?

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Question: Answered & Verified by Expert

If $A \subseteq B$, then which one of the following is not correct?

MathematicsProbabilityNDANDA 2015 (Phase 1)

Options:

A $\quad P(A \cap \bar{B})=0$
B $\quad P(A \mid B)=\frac{P(A)}{P(B)}$
C $\quad P(B \mid A)=\frac{P(B)}{P(A)}$
D $P(A \mid(A \cup B))=\frac{P(A)}{P(B)}$

Solution:

1865 Upvotes Verified Answer

The correct answer is: $\quad P(B \mid A)=\frac{P(B)}{P(A)}$

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