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If a body has a potential energy of $\left(4 x^2+2 x\right) J$ at a height of $2 \mathrm{~m}$, then the force acting on the body is
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The correct answer is:
$18 \mathrm{~N}$
Potential energy, $U=\left(4 x^2+2 x\right) J$
Force, $\mathrm{F}=\frac{\mathrm{dU}}{\mathrm{dx}}$
$\begin{aligned} & F=\frac{d}{d x}\left(4 x^2+2 x\right)=8 x+2 \\ & \text { at } x=82 m \\ & F=18 N\end{aligned}$
The force acting on the body is $18 \mathrm{~N}$.
Force, $\mathrm{F}=\frac{\mathrm{dU}}{\mathrm{dx}}$
$\begin{aligned} & F=\frac{d}{d x}\left(4 x^2+2 x\right)=8 x+2 \\ & \text { at } x=82 m \\ & F=18 N\end{aligned}$
The force acting on the body is $18 \mathrm{~N}$.
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