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If a change in current of $0.01 \mathrm{~A}$ in one coil produces a change in magnetic flux of $2 \times 10^{-2}$ weber in another coil, then the mutual inductance between coils is
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The correct answer is:
$2 \mathrm{H}$
Given, $\Delta I=0.01 \mathrm{~A}$
$$
\Delta \phi=2 \times 10^{-2} \mathrm{~Wb}
$$
We know that, $\Delta \phi=M \Delta I$ where, $M$ is mutual inductance between the coils.
$$
\begin{aligned}
\therefore & M=\frac{\Delta \phi}{\Delta I} \\
&=\frac{2 \times 10^{-2}}{0.01}=2 \mathrm{H}
\end{aligned}
$$
$$
\Delta \phi=2 \times 10^{-2} \mathrm{~Wb}
$$
We know that, $\Delta \phi=M \Delta I$ where, $M$ is mutual inductance between the coils.
$$
\begin{aligned}
\therefore & M=\frac{\Delta \phi}{\Delta I} \\
&=\frac{2 \times 10^{-2}}{0.01}=2 \mathrm{H}
\end{aligned}
$$
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