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If a charge on the body is \( 1 \mathrm{nC} \), then how many electrons are present on the body?
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Verified Answer
The correct answer is:
\( 6.25 \times 10^{9} \)
We know; $q=n e \Rightarrow n=\frac{q}{e}$
where $\mathrm{q}$ is charge; $\mathrm{n}$ is number of electrons; e is electronic charge
Given, $q=1 \mathrm{nC}=1 \times 10^{-9} \mathrm{C}$
If a charge on body is $1 \mathrm{nC}$, then $6.25 \times 10^{9}$
where $\mathrm{q}$ is charge; $\mathrm{n}$ is number of electrons; e is electronic charge
Given, $q=1 \mathrm{nC}=1 \times 10^{-9} \mathrm{C}$
If a charge on body is $1 \mathrm{nC}$, then $6.25 \times 10^{9}$
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