If A = ( cos 1 2 ∘ − cos 3 6 ∘ ) ( sin 9 6 ∘ + sin 2 4 ∘ ) and B = ( sin 6 0 ∘ − sin 1 2 ∘ ) ( cos 4 8 ∘ − cos 7 2 ∘ ) , then what is B A equal to?

Question

If A = ( cos 1 2 ∘ − cos 3 6 ∘ ) ( sin 9 6 ∘ + sin 2 4 ∘ ) and B = ( sin 6 0 ∘ − sin 1 2 ∘ ) ( cos 4 8 ∘ − cos 7 2 ∘ ) , then what is B A ​ equal to?, − 1, 1, 0, 2

MARKS App · Accepted Answer

Given A=\left(\cos 12^{\circ}-\cos 36^{\circ}ight)\left(\sin 96^{\circ}+\sin 24^{\circ}ight) \ B=\left(\sin 60^{\circ}-\sin 12^{\circ}ight)\left(\cos 48^{\circ}-\cos 72^{\circ}ight) \ & \frac{A}{B}=\frac{\left[2 \sin 24^{\circ} \sin 12^{\circ}ight]\left[2 \sin 60^{\circ} \cos 36^{\circ}ight]}{\left[2 \cos 36^{\circ} \sin 24^{\circ}ight]\left[2 \sin 60^{\circ} \sin 12^{\circ}ight]} \ & \Rightarrow \frac{A}{B}=1 \

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