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If $\mathrm{A}$ is a square matrix of order $\mathrm{n}>1$, then which one of the $\begin{array}{ll}\text { following is correct? } \end{array}$
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The correct answer is:
$\operatorname{det}(-\mathrm{A})=(-1)^{\mathrm{n}} \operatorname{det} \mathrm{A}$
$\mathrm{A}$ is square matrix of order $\mathrm{n}>1$. $\operatorname{det}(-\mathrm{A})=(-1)^{\mathrm{n}} \operatorname{det} \mathrm{A}$
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