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Question: Answered & Verified by Expert
If $\mathrm{A}$ is a square matrix, then the value of $\operatorname{adj} \mathrm{A}^{\mathrm{T}}-(\operatorname{adj} \mathrm{A})^{\mathrm{T}}$ is equal to
MathematicsMatricesNDANDA 2017 (Phase 2)
Options:
  • A A
  • B $2|\mathrm{~A}| \mathrm{I}$, where $\mathrm{I}$ is the identity matrix
  • C null matrix whose order is same as that of A
  • D unit matrix whose order is same as that of A
Solution:
1090 Upvotes Verified Answer
The correct answer is: null matrix whose order is same as that of A
We know, Adj $\mathrm{A}^{\mathrm{T}}=(\operatorname{adj} \mathrm{A})^{\mathrm{T}}$
$\therefore \mathrm{adj} \mathrm{A}^{\mathrm{T}}-(\mathrm{adj} \mathrm{A})^{\mathrm{T}}=\operatorname{adj} \mathrm{A}^{\mathrm{T}}-\mathrm{adj} \mathrm{A}^{\mathrm{T}}=0$

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