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If $A$ is the areal velocity of a planet of mass $M$, its angular momentum is
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Verified Answer
The correct answer is:
$2 M A$
According to Kepler's law of area, the areal velocity is given by
$A=\frac{L}{2 M}$
where, $L=$ angular momentum,
$M=$ mass of planet
and $\quad A=$ areal velocity.
Then, $L=2 M A$
$A=\frac{L}{2 M}$
where, $L=$ angular momentum,
$M=$ mass of planet
and $\quad A=$ areal velocity.
Then, $L=2 M A$
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