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If a leap year is selected at random, what is the chance that it will contain 53 tuesdays?
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A leap year has 366 days which contains 52 full weeks and 2 extra days. The extra days may occur as (Mon, Tue), (Tue, Wed), (Wed, Thu), (Thu, Fri), (Fri, Sat), (Sat, Sun), (Sun, Mon)
Now the favourable cases are (Mon, Tue), (Tue, Wed)
$\therefore \quad$ Probability that a leap year will have 53 Tuesday $=\frac{2}{7}$
Now the favourable cases are (Mon, Tue), (Tue, Wed)
$\therefore \quad$ Probability that a leap year will have 53 Tuesday $=\frac{2}{7}$
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