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Question: Answered & Verified by Expert
If a=limnk=1n2nn2+k2 and fx=1-cosx1+cosx,x0,1, then:
MathematicsDefinite IntegrationJEE MainJEE Main 2022 (26 Jul Shift 1)
Options:
  • A 22fa2=f'a2
  • B fa2f'a2=2
  • C 2fa2=f'a2
  • D fa2=2f'a2
Solution:
1636 Upvotes Verified Answer
The correct answer is: 2fa2=f'a2

Given, a=limnk=1n2nn2+k2

a=1nk=1n21+kn2=0121+x2dx

a=2tan-1x01

a=2π4-0=π2

Now, fx=1-cosx1+cosx

fx=tanx2;x0,1

So, fa2=fπ4

fπ4=2-1

And f'π4=12sec2π8=22+1

So, f'π4=2fπ4

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