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If a man of mass $50 \mathrm{~kg}$ is in a lift moving down with an acceleration equal to acceleration due to gravity, then the apparent weight of the man is
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The correct answer is:
$0$
The apparent weight of the man
$\begin{aligned} & =m(g-a)=50(9.8-9.8) \\ & =0\end{aligned}$
$\begin{aligned} & =m(g-a)=50(9.8-9.8) \\ & =0\end{aligned}$
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