If a metal crystallises in bcc structure with edge length of unit cell 4.29 × 10 - 8 cm the radius of metal atom is

Question

If a metal crystallises in bcc structure with edge length of unit cell 4.29 × 10 - 8 cm the radius of metal atom is, 3.2 × 10 - 7 c m, 1.86 × 10 - 8 c m, 1.07 × 10 - 7 c m, 1.07 × 10 - 8 c m

MARKS App · Accepted Answer

The relation between edge length and radius of an atom in a bcc structure is related as: r = 3 / 4 α Given, a = 4.29 × 10 - 8 c m For bcc structure, r = 3 4 a = 3 4 × 4.29 × 10 - 8 c m = 1.857 × 10 - 8 c m ≃ 1.86 × 10 - 8 c m

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