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If a new planet is discovered rotating around Sun with the orbital radius double that of earth, then what will be its time period (in earth's days)
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$1032$
$T^2 \propto R^3 \Rightarrow\left(\frac{T_P}{T_E}\right)^2=\left(\frac{R_P}{R_E}\right)^3=\left(\frac{2 R_E}{R_E}\right)^3$
$\begin{aligned} & \frac{T_P}{T_E}=(2)^{3 / 2}=2 \sqrt{2} \\ \Rightarrow & T_P=2 \sqrt{2} \times 365=1032.37=1032 \text { days }\end{aligned}$
$\begin{aligned} & \frac{T_P}{T_E}=(2)^{3 / 2}=2 \sqrt{2} \\ \Rightarrow & T_P=2 \sqrt{2} \times 365=1032.37=1032 \text { days }\end{aligned}$
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