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If a normal drawn to the parabola $y^2=4 a x$ at the point $(a, 2 a)$ meets parabola again on $\left(a t^2, 2 a t\right)$, then the value of $t$ will be
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Verified Answer
The correct answer is:
$-3$
We know that
$t_2=-t_1-\frac{2}{t_1}$
Put $t_1=1$ and $t_2=t$. Hence $t=-3$.
$t_2=-t_1-\frac{2}{t_1}$
Put $t_1=1$ and $t_2=t$. Hence $t=-3$.
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