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If a number is chosen at random from the set $\{1,2,3, \ldots \ldots, 100\}$, then the probability that the chosen number is a perfect cube is
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The correct answer is:
$1 / 25$
$\begin{aligned} & n(S)=100 \\ & E=\{1,8 ; 27,64\} \\ & n(E)=4\end{aligned}$
$\therefore$ Required probability $=p(E)=\frac{n(E)}{n(S)}=\frac{4}{100}=\frac{1}{25}$
$\therefore$ Required probability $=p(E)=\frac{n(E)}{n(S)}=\frac{4}{100}=\frac{1}{25}$
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