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If a plane electromagnetic wave has electric field oscillations of frequency $3 \mathrm{GHz}$ then the wavelength of the wave is
(speed of light in vacuum $=3 \times 10^8 \mathrm{~ms}^{-1}$ )
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(speed of light in vacuum $=3 \times 10^8 \mathrm{~ms}^{-1}$ )
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Verified Answer
The correct answer is:
$100m$
Frequency of osciliations,
$\mathrm{f}=3 \mathrm{GHz}=3 \times 10^6 \mathrm{~Hz}$
Wavelength of wave, $\lambda=\frac{\mathrm{c}}{\mathrm{f}}$
$\begin{aligned}
& =\frac{3 \times 10^8}{3 \times 10^6} \\
& =100 \mathrm{~m}
\end{aligned}$
$\mathrm{f}=3 \mathrm{GHz}=3 \times 10^6 \mathrm{~Hz}$
Wavelength of wave, $\lambda=\frac{\mathrm{c}}{\mathrm{f}}$
$\begin{aligned}
& =\frac{3 \times 10^8}{3 \times 10^6} \\
& =100 \mathrm{~m}
\end{aligned}$
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