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If a proton and anti-proton come close to each other and annihilate, how much energy will be released?
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Verified Answer
The correct answer is:
$3 \times 10^{-10} \mathrm{~J}$
Mass of proton $=$ mass of anti-proton
$=1.67 \times 10^{-27} \mathrm{~kg}=1 \mathrm{amu}$
Energy equivalent to $1 \mathrm{amu}=931 \mathrm{MeV}$.
So, energy equivalent to $2 \mathrm{amu}=2 \times 931 \mathrm{MeV}$
$\begin{aligned} & =1862 \times 10^6 \times 1.6 \times 10^{-19} \\ & =2.97 \times 10^{-10} \mathrm{~J} \\ & =3 \times 10^{-10} \mathrm{~J}\end{aligned}$
$=1.67 \times 10^{-27} \mathrm{~kg}=1 \mathrm{amu}$
Energy equivalent to $1 \mathrm{amu}=931 \mathrm{MeV}$.
So, energy equivalent to $2 \mathrm{amu}=2 \times 931 \mathrm{MeV}$
$\begin{aligned} & =1862 \times 10^6 \times 1.6 \times 10^{-19} \\ & =2.97 \times 10^{-10} \mathrm{~J} \\ & =3 \times 10^{-10} \mathrm{~J}\end{aligned}$
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