If a radioactive substance reduces to 1 1 6 of its original mass in 40 days, its half-life is

Question

If a radioactive substance reduces to 1 1 6 of its original mass in 40 days, its half-life is, 10 days, 20 days, 40 days, None of these

MARKS App · Accepted Answer

From the formula N = N 0 1 2 n N 1 6 = N 0 1 2 n N 0 = original number of atom 1 2 4 = 1 2 n ⇒ n = 4 4 half lives ∴ 4 T 1 / 2 = 4 0 4 T 1 / 2 = 4 0 4 = 1 0 days

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