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Question: Answered & Verified by Expert
If a simple pendulum oscillates with an amplitude of $50 \mathrm{~mm}$ and time period of $2 \mathrm{~s}$, then its maximum velocity is
PhysicsOscillationsMHT CETMHT CET 2009
Options:
  • A $0.10 \mathrm{~ms}^{-1}$
  • B $0.15 \mathrm{~ms}^{-1}$
  • C $0.8 \mathrm{~ms}^{-1}$
  • D $0.26 \mathrm{~ms}^{-1}$
Solution:
1420 Upvotes Verified Answer
The correct answer is: $0.15 \mathrm{~ms}^{-1}$
$v_{\max }=a \omega=a \times \frac{2 \pi}{T}=\left(50 \times 10^{-3}\right) \times \frac{2 \pi}{2}$
$=0.15 \mathrm{~ms}^{-1}$

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