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If $A=\sin ^2 x+\cos ^4 x$, then for all real $x$
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The correct answer is:
$\frac{3}{4} \leq \mathrm{A} \leq 1$
$\frac{3}{4} \leq \mathrm{A} \leq 1$
$A=\sin ^2 x+\cos ^4 x=\frac{7+\cos 4 x}{8} \Rightarrow \frac{3}{4} \leq A \leq 1$
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