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If a species has 16 protons, 18 electrons and 16 neutrons, find the species and its charge
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The correct answer is:
$\mathrm{S}^{2-}$
Hints : $16 \mathrm{p}$ means $\mathrm{z}=16$
$18 \mathrm{e}^{-}$means, 2 unit negative charge is present.
Hence species is $\mathrm{S}^{-2}$
$18 \mathrm{e}^{-}$means, 2 unit negative charge is present.
Hence species is $\mathrm{S}^{-2}$
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