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If a variable takes values $0,1,2,3, \ldots, \mathrm{n}$ with frequencies $1, \mathrm{C}(\mathrm{n}, 1), \mathrm{C}(\mathrm{n}, 2), \mathrm{C}(\mathrm{n}, 3), \ldots, \mathrm{C}(\mathrm{n}, \mathrm{n})$ respectively, then the
$\begin{array}{ll}\text { arithmetic mean is } & {}\end{array}$
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$\begin{array}{ll}\text { arithmetic mean is } & {}\end{array}$
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Verified Answer
The correct answer is:
$\mathrm{n}+1$
The arithmetic mean is always between minimum and maximum value.
So, $\frac{\mathrm{n}}{2}$ is arithmetic mean.
So, $\frac{\mathrm{n}}{2}$ is arithmetic mean.
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