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Question: Answered & Verified by Expert
If a=xi^+yj^+zk^, b=ı^+j^+k^ where x,y,z0,3,-3,6,-6, then the number of non-zero vectors a such that a·b=0 are
MathematicsVector AlgebraJEE Main
Options:
  • A 20
  • B 18
  • C 15
  • D 12
Solution:
2231 Upvotes Verified Answer
The correct answer is: 18
a·b=x+y+z=0
If x=3,y=-3,z=0, i.e. 3!=6
If x=6,y=-6,z=0, i.e.3!=6
If x=6,y=-3,z=-3, i.e.3!2!=3
If x=-6,y=3,z=3, i.e.=3!2!=3
Total number of vectors =18

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