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If $A=\{x: x$ is a multiple of 4$\}$ and, $B=\{x: x$ is a multiple of 6$\}$, then $A \cap B$ consists of multiples of
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The correct answer is:
12
12
Let $x \in A \cap B$. Then,
$x \in A$ and $x \in B$
$\Rightarrow x$ is a multiple of 4 and $x$ is a multiple of 6
$\Rightarrow x$ is a multiple of 4 and 6 both
$\therefore x$ is a multiple of 12
$x \in A$ and $x \in B$
$\Rightarrow x$ is a multiple of 4 and $x$ is a multiple of 6
$\Rightarrow x$ is a multiple of 4 and 6 both
$\therefore x$ is a multiple of 12
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