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If \( A=1 \) and \( B=0 \), then in terms of Boolean algebra, \( \bar{A}+B= \)
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The correct answer is:
\( B \)
\( A=1, B=0 \)
\( \bar{A}+B=1+0=0+0=0 \)
\( \bar{A}+B=B \)
\( \bar{A}+B=1+0=0+0=0 \)
\( \bar{A}+B=B \)
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