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Question: Answered & Verified by Expert
If \( a_{k} \) is the coefficient of \( x^{k} \) in the expansion of \( \left(1+x+x^{2}\right)^{n} \) for \( k=0,1,2, \ldots ., 2 n \) then value of
\( a_{1}+2 a_{2}+3 a_{3}+\ldots \ldots \ldots 2 n a_{2 n} \) is:
MathematicsBinomial TheoremJEE Main
Options:
  • A \( -a_{0} \)
  • B \( 3^{n} \)
  • C \( n \cdot 3^{n+1} \)
  • D \( n \cdot 3^{n} \)
Solution:
2090 Upvotes Verified Answer
The correct answer is: \( n \cdot 3^{n} \)

We expand the equation by using binomial expansion,

1+x+x2n=a0+a1x+a2x3+....+a2nx2n


On differentiating both sides, we get
n(1+x+x2)n-11+2x=a1+2a2x+3a3x2
+...+2na2nx2n-1


Now, on putting x=1, we get
n(3)n-13=a1+2a2+3a3+...+2na2n
a1+2a2+3a3+....+2na2n=n3n

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