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If \( a_{k} \) is the coefficient of \( x^{k} \) in the expansion of \( \left(1+x+x^{2}\right)^{n} \) for \( k=0,1,2, \ldots ., 2 n \) then value of
\( a_{1}+2 a_{2}+3 a_{3}+\ldots \ldots \ldots 2 n a_{2 n} \) is:
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\( a_{1}+2 a_{2}+3 a_{3}+\ldots \ldots \ldots 2 n a_{2 n} \) is:
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2090 Upvotes
Verified Answer
The correct answer is:
\( n \cdot 3^{n} \)
We expand the equation by using binomial expansion,
....
On differentiating both sides, we get
+...
Now, on putting , we get
...
....
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