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Question: Answered & Verified by Expert
If \(A=\left[\begin{array}{lll}2 & 0 & 0 \\ 2 & 2 & 0 \\ 2 & 2 & 2\end{array}\right]\), then \(\operatorname{adj}(\operatorname{adj} A)\) is equal to -
MathematicsMatricesJEE Main
Options:
  • A \(8\left[\begin{array}{lll}1 & 0 & 0 \\ 1 & 1 & 0 \\ 1 & 1 & 1\end{array}\right]\)
  • B \(16\left[\begin{array}{lll}1 & 0 & 0 \\ 1 & 1 & 0 \\ 1 & 1 & 1\end{array}\right]\)
  • C \(64\left[\begin{array}{lll}1 & 0 & 0 \\ 1 & 1 & 0 \\ 1 & 1 & 1\end{array}\right]\)
  • D None of these
Solution:
1340 Upvotes Verified Answer
The correct answer is: \(16\left[\begin{array}{lll}1 & 0 & 0 \\ 1 & 1 & 0 \\ 1 & 1 & 1\end{array}\right]\)
\(|A|=\left[\begin{array}{lll}
2 & 0 & 0 \\
2 & 2 & 0 \\
2 & 2 & 2
\end{array}\right]=(2)(2)(2)=8\)
Now adj \((\operatorname{adj} A)=|\mathrm{A}|^{3-2} \mathrm{~A}\)
\(=8\left[\begin{array}{lll}
2 & 0 & 0 \\
2 & 2 & 0 \\
2 & 2 & 2
\end{array}\right]=16\left[\begin{array}{ccc}
1 & 0 & 0 \\
1 & 1 & 0 \\
1 & 1 & 1
\end{array}\right]\)

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