If all symbols have their usual meaning, then for a non-volatile non-electrolyte solute $ \operatorname{Lt}_{\mathrm{m} \rightarrow 1}\left(\frac{\Delta \mathrm{T}_{\mathrm{f}}}{\mathrm{m}}\right) $ is equal to:

Question

If all symbols have their usual meaning, then for a non-volatile non-electrolyte solute $ \operatorname{Lt}_{\mathrm{m} \rightarrow 1}\left(\frac{\Delta \mathrm{T}_{\mathrm{f}}}{\mathrm{m}}\right) $ is equal to:, Zero, Infinity, $ \Delta \mathrm{T}_{f} $, $ \mathrm{K}_{f} $

MARKS App · Accepted Answer

For a non-volatile non-electrolyte solute, depression in freezing point Δ T f ⁡ = K f ⁡ m or Δ T f ⁡ m = K f ⁡ Lt m → 1 Δ T f m = K f ⁡

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