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Question: Answered & Verified by Expert
If an electron in a hydrogen atom jumps from the third orbit to the second orbit, it emits a photon of wavelength λ. When it jumps from the fourth orbit to the third orbit, the corresponding wavelength of the photon will be
PhysicsAtomic PhysicsNEETNEET 2016 (Phase 2)
Options:
  • A 1625λ
  • B 916λ
  • C 207λ
  • D 2013λ
Solution:
1374 Upvotes Verified Answer
The correct answer is: 207λ

1λ=R1n12-1n22

λ=1R122-132

λ=1R132-142

λλ=122-132132-142λ=207λ.

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