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If an electron is moving in the $4^{\text {th }}$ orbit of the hydrogen atom then the angular momentum of the electron in SI units is
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Verified Answer
The correct answer is:
$\frac{2h}{\pi}$
Given, $\mathrm{n}=4$
$\begin{aligned}
& \text { Angular momentum, } \mathrm{L}=\mathrm{n} \frac{\mathrm{h}}{2 \pi} \\
& =4 \times \frac{\mathrm{h}}{2 \pi} \\
& =\frac{2 \mathrm{~h}}{\pi}
\end{aligned}$
$\begin{aligned}
& \text { Angular momentum, } \mathrm{L}=\mathrm{n} \frac{\mathrm{h}}{2 \pi} \\
& =4 \times \frac{\mathrm{h}}{2 \pi} \\
& =\frac{2 \mathrm{~h}}{\pi}
\end{aligned}$
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