Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
If  α and β are the roots of the equation, 7x2-3x-2=0, then the value ofα1-α2+β1-β2 is equal to:
MathematicsQuadratic EquationJEE MainJEE Main 2020 (05 Sep Shift 2)
Options:
  • A 2732
  • B 124
  • C 38
  • D 2716
Solution:
2457 Upvotes Verified Answer
The correct answer is: 2716
Given α and β are the roots of the equation,7x2-3x-2=0, then 

α+β=37 ; αβ=-27

Now 

α1-α2+β1-β2=(α+β)-αβ(α+β)1-α21-β2=(α+β)-αβ(α+β)1+(αβ)2-α2+β2

(α+β)-αβ(α+β)1+(αβ)2-(α+β)2+2αβ=37+27371+272-372-227=2716

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.