If α and β are the roots of x 2 + 2 x − 3 = 0 and γ , δ are the roots of y 2 − y − 4 = 0 , then the equation of the circle having ( α , γ ) and ( β , δ ) as ends of a diameter is

Question

If α and β are the roots of x 2 + 2 x − 3 = 0 and γ , δ are the roots of y 2 − y − 4 = 0 , then the equation of the circle having ( α , γ ) and ( β , δ ) as ends of a diameter is, x 2 + y 2 + 4 x − 3 y + 2 = 0, x 2 + y 2 + 2 x − y + 7 = 0, x 2 + y 2 − 3 x + 4 y + 1 = 0, x 2 + y 2 − 2 x + y − 1 = 0

MARKS App · Accepted Answer

Given, data is incorrect because y 2 − y + 4 = 0 has imaginary discriminant and never gives equal to zero.

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