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Question: Answered & Verified by Expert
If $\alpha, \beta, \gamma$ are the roots of $x^3-2 x^2+4 x-1=0$ then the equation having the roots $\beta \gamma+\frac{1}{\alpha}, \alpha \beta+\frac{1}{\gamma}, \gamma \alpha+\frac{1}{\beta}$ is
MathematicsQuadratic EquationAP EAMCETAP EAMCET 2018 (24 Apr Shift 2)
Options:
  • A $x^3+8 x^2-8 x+8=0$
  • B $x^3-8 x^2+16 x-8=0$
  • C $x^3-8 x^2+8 x-8=0$
  • D $x^3-4 x^2+8 x-16=0$
Solution:
1438 Upvotes Verified Answer
The correct answer is: $x^3-8 x^2+8 x-8=0$
No solution. Refer to answer key.

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