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If $\mathrm{BaCl}_2$ ionizes to an extent of $80 \%$ in aqueous solution, the value of van't Hoff factor is
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Verified Answer
The correct answer is:
2.6
$\mathrm{BaCl}_2(s) \stackrel{\mathrm{H}_2 \mathrm{O}}{\longrightarrow} \mathrm{Ba}^{2+}+2 \mathrm{Cl}^{-}$
$\begin{array}{cccl}1 & & 0 & 0 & \\ 1-0.8 & & 0.8 & 2 \times 0.8 & \text { In aq. solution }\end{array}$
$i=\frac{\text { No. of moles after reaction }}{\text { Initial number of moles }}$
$=\frac{1-0.8+0.8+(2 \times 0.8)}{1}$
$=2.6$
$\begin{array}{cccl}1 & & 0 & 0 & \\ 1-0.8 & & 0.8 & 2 \times 0.8 & \text { In aq. solution }\end{array}$
$i=\frac{\text { No. of moles after reaction }}{\text { Initial number of moles }}$
$=\frac{1-0.8+0.8+(2 \times 0.8)}{1}$
$=2.6$
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