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If $C$ be the capacitance and $V$ be the electric potential, then the dimensional formula of $C V^{2}$ is
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Verified Answer
The correct answer is:
$\left[\mathrm{ML}^{2} \mathrm{~T}^{-2} \mathrm{~A}^{0}\right]$
We know,
Energy, $E=C V^{2}$
Dimensions of $C V^{2}=$ Dimensions of energy
$$
=\left[\mathrm{ML}^{2} \mathrm{~T}^{-2}\right]
$$
Energy, $E=C V^{2}$
Dimensions of $C V^{2}=$ Dimensions of energy
$$
=\left[\mathrm{ML}^{2} \mathrm{~T}^{-2}\right]
$$
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