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Question: Answered & Verified by Expert
If CrCr25 and C0+5C1+9C2++101C25=225k, then k is equal to ____________.
MathematicsBinomial TheoremJEE MainJEE Main 2020 (09 Jan Shift 2)
Solution:
1885 Upvotes Verified Answer
The correct answer is: 51

r=0254r+125Cr

=4r=025r.25Cr+r=025Cr25
=4r=125r×25rCr-124+225

=100r=125Cr-125+225
=100.224+225

=22550+1

=51.225
So, k=51

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