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Question: Answered & Verified by Expert
If $\mathrm{C}(s)+\mathrm{O}_{2}(g) \longrightarrow \mathrm{CO}_{2}(g) ; \Delta H=r$
and $\mathrm{CO}(g)+\frac{1}{2} \mathrm{O}_{2} \longrightarrow \mathrm{CO}_{2}(g): \Delta H=s$
then, the heat of formation of $\mathrm{CO}$ is
ChemistryThermodynamics (C)MHT CETMHT CET 2008
Options:
  • A $r+s$
  • B $r-s$
  • C $s-r$
  • D $\mathrm{rs}$
Solution:
2119 Upvotes Verified Answer
The correct answer is: $r-s$
$\mathrm{C}(s)+\mathrm{O}_{2}(g) \rightarrow \mathrm{CO}_{2}(g) ; \Delta H=r$ ...(i)
$\mathrm{CO}(g)+\frac{1}{2} \mathrm{O}_{2}(g) \rightarrow \mathrm{CO}_{2}(g) ; \Delta H=s$ ...(ii)
$\mathrm{C}(s)+\frac{1}{2} \mathrm{O}_{2}(g) \longrightarrow \mathrm{CO}(g) ; \Delta H=?$
Subtract Eq. (ii) from Eq. (i)

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