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If $\cos 3 \theta=\alpha \cos \theta+\beta \cos ^3 \theta$, then $(\alpha, \beta)=$
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The correct answer is:
$(-3,4)$
Given that $\cos 3 \theta=\alpha \cos \theta+\beta \cos ^3 \theta$ But $\cos 3 \theta=4 \cos ^3 \theta-3 \cos \theta \Rightarrow(\alpha, \beta)=(-3,4)$
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