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If \( \cos x=|\sin x| \) then, the general solution is
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The correct answer is:
\( x=2 n \pi \pm \frac{\Pi}{4}, n \in z \)
(A)
$\cos x=|\sin x|$
$\Rightarrow \pm \cos x=\sin x$
$\Rightarrow \tan x=\pm 1$
$x=n \pi \pm \frac{\Pi}{4}, n \in z$, but $\cos x$ is positive so $x=2 n \pi \pm \frac{\Pi}{4}, n \in z$
$\cos x=|\sin x|$
$\Rightarrow \pm \cos x=\sin x$
$\Rightarrow \tan x=\pm 1$
$x=n \pi \pm \frac{\Pi}{4}, n \in z$, but $\cos x$ is positive so $x=2 n \pi \pm \frac{\Pi}{4}, n \in z$
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