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If $\operatorname{cosec} A+\cot A=\frac{11}{2}$, then $\tan A=$
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Verified Answer
The correct answer is:
$\frac{44}{117}$
$\begin{gathered}
\operatorname{cosec} A+\cot A=\frac{11}{2} \Rightarrow \operatorname{cosec} A-\cot A=\frac{2}{11} \\
\text { Therefore } 2 \cot A=\frac{117}{22} \Rightarrow \tan A=\frac{44}{117}
\end{gathered}$
\operatorname{cosec} A+\cot A=\frac{11}{2} \Rightarrow \operatorname{cosec} A-\cot A=\frac{2}{11} \\
\text { Therefore } 2 \cot A=\frac{117}{22} \Rightarrow \tan A=\frac{44}{117}
\end{gathered}$
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