If d d x x 4 + x 2 + 1 x 2 + x + 1 = a x + b , then a

d d x x 4 + x 2 + 1 x 2 + x + 1 = d d x x 2 + x + 1 x 2 - x + 1 x 2 + x + 1 = d d x ( x 2 - x + 1 ) = 2 x - 1 a = 2 , b = - 1 a - b = 3

Question: Answered & Verified by Expert

\frac{d}{d x} (\frac{x^{4} + x^{2} + 1}{x^{2} + x + 1}) = a x + b,

then

a - b =

MathematicsDifferentiationAP EAMCETAP EAMCET 2020 (23 Sep Shift 1)

Options:

Solution:

1421 Upvotes Verified Answer

The correct answer is:

3

$\frac{d}{d x} (\frac{x^{4} + x^{2} + 1}{x^{2} + x + 1})$

$= \frac{d}{d x} (\frac{(x^{2} + x + 1) (x^{2} - x + 1)}{x^{2} + x + 1})$

$= \frac{d}{d x} (x^{2} - x + 1) = 2 x - 1$

$a = 2, b = - 1$

$a - b = 3$

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.