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Question: Answered & Verified by Expert
If dxx2+x=lnfx+C (where C is the constant of integration), then the range of y=fx, xR--1,0 is
MathematicsIndefinite IntegrationJEE Main
Options:
  • A R-1
  • B R-0
  • C R-0,1
  • D R-0,-1
Solution:
2932 Upvotes Verified Answer
The correct answer is: R-0,1
Ι=dxxx+1=dxx-dxx+1
Ι=lnx-lnx+1+C
=lnxx+1+C
i.e. y=fx=xx+1
 yx+y=x
x=y1-y
yR-0,1 as x0

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