If Ι = ∫ d x x 3 x 8 + 1 3 / 4 = λ 1 + x 8 1 4 x 2 + c (where c is the constant of integration), then the value of λ is equal to

Question

If Ι = ∫ d x x 3 x 8 + 1 3 / 4 = λ 1 + x 8 1 4 x 2 + c (where c is the constant of integration), then the value of λ is equal to, 2, 1 2, - 2, - 1 2

MARKS App · Accepted Answer

Ι = ∫ x - 9 1 + x - 8 3 4 d x Let, 1 + x - 8 = t - 8 x - 9 d x = d t Ι = ∫ - d t 8 t 3 / 4 = - 1 8 ∫ t - 3 / 4 d t = - 1 8 t 1 / 4 1 4 + c = - 1 + x - 8 1 / 4 2 + c = - 1 + x 8 1 / 4 2 x 2 + c ⇒ λ = - 1 2

Search any question & find its solution

Looking for more such questions to practice?