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If dielectric is inserted in charged capacitor (battery removed), then quantity that remains constant is
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The correct answer is:
charge
Variation of different variables (Q, $C, V, E$ and $U$ ) of parallel plate capacitor when dielectric $(K)$ is introduced when battery is removed is
$$
\begin{array}{ll}
C^{\prime}=K C & E^{\prime}=E / K \\
Q^{\prime}=Q & U^{\prime}=U / K \\
V^{\prime}=V / K &
\end{array}
$$
$$
\begin{array}{ll}
C^{\prime}=K C & E^{\prime}=E / K \\
Q^{\prime}=Q & U^{\prime}=U / K \\
V^{\prime}=V / K &
\end{array}
$$
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