$\text{I}=\int \frac{\text{dx}}{{\left(\frac{\text{x}-1}{\text{x}+2}\right)}^4{\left(\text{x}+2\right)}^2}\text{ put }\frac{\text{x}-1}{\text{x}+2}=\text{t}$

On solving, we get,

$\mathrm{I}=\frac{4}{3}{\left(\frac{\mathrm{x}-1}{\mathrm{x}+2}\right)}^{\frac{1}{4}}+\mathrm{c}$

$\text{k}=\frac{4}{3}\Rightarrow 30\text{k}=40=2^3\times 5^1$

Hence, total divisors are $4\times 2 = 8$