If E A 1 and E A 2 for oxygen atom - 142 k J m o l - 1 and + 844 k J m o l - 1 . The energy released form 2 O + 2 e - → 2 O - will be

Question

If E A 1 and E A 2 for oxygen atom - 142 k J m o l - 1 and + 844 k J m o l - 1 . The energy released form 2 O + 2 e - → 2 O - will be, - 986 k J m o l - 1, - 702 k J m o l - 1, - 284 k J m o l - 1, - 1688 k J m o l - 1

MARKS App · Accepted Answer

O + e - → O - Δ H = - 142 k J m o l - 1 So 2 O + 2 e - → 2 O - Δ H = 2 × ( - 142 ) = - 284 k J m o l - 1

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